Hello!
The pH of the solution is 4,13
This solution is a typical example of a buffer solution, in which a weak acid and its conjugate base are together and resists the addition of acids or bases. For calculating the pH of a buffer solution, we use the Henderson-Hasselbach equation, which is the following:
[tex]pH=pKa+log( \frac{ [A^{-}]}{[HA]}) \\ \\ pH=3,77+log (\frac{0,230M}{0,100M})\\ \\ pH= 4,13[/tex]
Have a nice day!
