A 1500 kg car Coast down a hill starting from rest and decreases its high by 22 M over a distance of 100 m of travel how fast will it be going at the end of the Hill if friction has no effect in slowing its motion
To solve this:Initial KE = 0 J meaning it begins at rest ΔKE = ΔGPE meaning there is no friction let speed at bottom of hill = v so (1/2)mv² = mgΔh v² = 2gΔh v = √[2 * 9.8 * 22] v = 21 m/s would be the answer if friction has no effect in slowing its motion
