angeladahlgren1970 angeladahlgren1970
  • 19-04-2018
  • Physics
contestada

What is the internal energy of 2.00 mol of an ideal diatomic gas at 765 k , assuming all degrees of freedom are active?

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skyluke89
skyluke89 skyluke89
  • 29-04-2018
The internal energy of an ideal gas is given by:
[tex]U= \frac{k}{2}nRT [/tex]
where 
k is the number of degrees of freedom of the molecules of the gas
n is the number of moles
R is the gas constant
T is the absolute temperature.

For a diatomic gas, k=5. In our problem, the number of moles is n=2.00 and the absolute temperature of the gas is T=765 K, so its internal energy is
[tex]U= \frac{5}{2}nRT= \frac{5}{2}(2.00 mol)(8.31 J/mol K)(765 K)=3.18 \cdot 10^4 J [/tex]
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