whoUnknown whoUnknown
  • 20-04-2018
  • Mathematics
contestada

which equation has the same solution 2x²+16x-10=0

a.(x+4)²= -3
b.(x+4)²= -11
C..(x+4)²= 13
d.(x+4)²= 21

Respuesta :

calculista
calculista calculista
  • 20-04-2018
2x²+16x-10=0

is equivalent to:     (divide by two)

x²+8x-5=0

The answer is d. (x+4)²= 21

Because,

(x+4)²= 21

x² + 8x +16 = 21

x² + 8x +16  -21= 0

x² + 8x - 5= 0




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