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given the equation of the circle x2+6x+y2=7 use completing the square and factoring to write the equation in standard form
[tex]x {}^{2} + 6x + y {}^{2} = 7[/tex]
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Respuesta :

calculista
x2+6x+y2=7

We add 9 to each side of the equation

x2+6x+y2 + 9 =7 + 9

(x+3)**2 + (y+0)**2 = 16

(x+3)**2 + (y+0)**2 = 4**2            (Standard form)


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