mequitalturnerb mequitalturnerb
  • 20-04-2018
  • Mathematics
contestada

What is the solution to the equation ? sqrt 2n+28-4 sqrt n=0?

n=2
n=4
n=7
n=14

PLEASE HELP ASAP

Respuesta :

Stiaen
Stiaen Stiaen
  • 20-04-2018
Hello !

[tex]\sqrt{2n+28}-4\sqrt{n}=0\\\\\sqrt{2n+28}=4\sqrt{n}\\\\\sqrt{2n+28}^2=\left(4\sqrt{n}\right)^2\\\\2n+28=16n\\\\2n-16n=-28\\\\14n=28\\\\\boxed{\boxed{n=2}}[/tex]
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20anderpre
20anderpre 20anderpre
  • 21-11-2018

Just took the test it. Is n=2

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