contestada

A researcher raises the temperature from 72.8 to 92.3 o C and finds that the rate of the reaction doubles. What was the activation energy (in J/mol) for this reaction? (R = 8.3145 J/mol K)

Respuesta :

akande212

Answer:

E = 37467J/mol = 37.5kJ

Explanation:

Please see attachment below.

The equation that relates two rates of reaction (Arrhenius equation) is what is used to solve this kinds of problem the equation is given as follows.

r1l2/r1= e^-E/R×(1/T2–1/T1)

Where

r1 = initial rate of reaction

r2 = final rate of reaction

E = Activation energy

T1, T2 = initial and final temperatures.

R = gas constant = 8.314J/milk

Ver imagen akande212

Otras preguntas